What are increasing and decreasing functions, and why are they so essential for studying mathematics? This concept helps us understand how a function behaves over different intervals. By grasping these properties, we can not only plot graphs but also analyze real-world processes described by mathematical models.
Increasing and Decreasing Functions: How Does It Work?
How do you know when a function is increasing or decreasing? It’s a common question when diving into mathematics. Here’s the simple idea:
- A function is increasing on a given interval if, as x increases, the value of f(x) also increases. In other words, for any x1<x2, the inequality f(x1)<f(x2) holds;
- A function is decreasing if, as x increases, f(x) This means that for x1<x2, we have f(x1)>f(x2).
But how can you figure out whether a function is increasing or decreasing without plotting its graph? That’s where derivatives come in handy.
The Derivative: A Powerful Analysis Tool
Have you ever wondered how mathematicians determine whether a function is increasing or decreasing without plugging in countless values? The secret lies in the derivative. The derivative of a function, f'(x), indicates how the function changes at each point:
- If f'(x)>0 on a particular interval, the function is increasing;
- If f'(x)<0, the function is decreasing;
- If f'(x)=0, this may indicate a critical point—a potential maximum, minimum, or inflection point.
How to Determine Increasing and Decreasing Intervals: Step-by-Step
So, how can you identify where a function increases or decreases? Follow these steps:
- Calculate the derivative f'(x).
- Find critical points by solving the equation f'(x)=0.
- Divide the domain of the function into intervals using the critical points.
- Analyze the sign of the derivative on each interval: if f'(x)>0, the function is increasing; if f'(x)<0, it’s decreasing.
Practical Examples: Learn by Solving
Understanding the theory is great, but the best way to learn is by solving problems. How do you determine whether a function is increasing or decreasing, and on which intervals? Let’s explore 4 examples, starting from the simplest and gradually tackling more complex cases—with detailed explanations.
Example 1: Find the Intervals of Increase and Decrease for f(x)=x2

First, find the derivative and set it to zero to locate critical points:
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The critical point is x=0. Divide the domain into two intervals: (-∞; 0) and (0; +∞). Check the sign of the derivative on each interval:
- For x∈(-∞; 0), let x=-1: f'(-1)=2⋅(-1)=-2<0. The function is decreasing;
- For x∈(0; +∞), let x=1: f'(1)=2⋅1=2>0. The function is increasing.
Thus, the function decreases on (-∞; 0) and increases on (0; +∞).
Example 2: Find the Intervals of Increase and Decrease for f(x)=-x2+4⋅x

Start with the derivative:
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The critical point is x=2. Divide the domain into: (-∞; 2) and (2; +∞). Analyze the sign of the derivative:
- For x∈(-∞; 2), let x=1: f'(1)=-2⋅1+4=2>0. The function is increasing;
- For x∈(2; +∞), let x=3: f'(3)=-2⋅3+4=-2<0. The function is decreasing.
Thus, the function increases on (-∞; 2) and decreases on (2; +∞).
Example 3: Find the Intervals of Increase and Decrease for f(x)=x3-3⋅x

Calculate the derivative and find critical points:
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Critical points are x=-1 and x=1. Divide the domain into three intervals: (-∞; -1), (-1; 1) and (1; +∞). Test the derivative:
- For x∈(-∞; -1), let x=-2: f'(-2)=3⋅(-2)2-3=9>0. The function is increasing;
- For x∈(-1; 1), let x=0: f'(0)=3⋅02-3=-3<0. The function is decreasing;
- For x∈(1; +∞), let x=2: f'(2)=3⋅22-3=9>0. The function is increasing.
Thus, the function increases on (-∞; -1)∪(1; +∞) and decreases on (-1; 1).
Example 4: Find the Intervals of Increase and Decrease for f(x)=x4-4⋅x2

Start by calculating the derivative and finding the critical points:
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The critical points are x=√-2, x=0, x=√2. Divide the domain into four intervals: (-∞; √-2), (√-2; 0), (0; √2) and (√2; +∞). Analyze the sign of the derivative on each interval:
- For x∈(-∞; √-2), let x=-2: f'(-2)=4⋅(−2)3-8⋅(-2)=-32<0. The function is decreasing;
- For x∈(√-2; 0), let x=-1: f'(-1)=4⋅(-1)3-8⋅(-1)=4>0. The function is increasing;
- For x∈(0; √2), let x=1: f'(1)=4⋅13-8⋅1=-4<0. The function is decreasing;
- For x∈(√2; +∞), let x=2: f'(2)=4⋅23-8⋅2=32>0. The function is increasing.
Thus, the function decreases on (-∞; √-2)∪(0; √2) and increases on (√-2; 0)∪(√2; +∞).
Looking Deeper: Beyond Increasing and Decreasing
Want to understand even more about functions? Besides increase and decrease, here are other critical aspects of their behavior:
- Range of the Function – This includes all possible values y=f(x) can take.
- Maximum and Minimum Values – Finding the highest or lowest point of a function is crucial for optimization problems.
- Points of Discontinuity – Learn how to identify and understand interruptions in a function’s graph.